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-\frac{2}{x+1}
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-\frac{2}{x+1}
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\frac{3x+1}{\left(x-1\right)\left(x+1\right)}+\frac{2}{1-x}-\frac{3}{1+x}
Factor x^{2}-1.
\frac{3x+1}{\left(x-1\right)\left(x+1\right)}+\frac{2\left(-1\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}-\frac{3}{1+x}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of \left(x-1\right)\left(x+1\right) and 1-x is \left(x-1\right)\left(x+1\right). Multiply \frac{2}{1-x} times \frac{-\left(x+1\right)}{-\left(x+1\right)}.
\frac{3x+1+2\left(-1\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}-\frac{3}{1+x}
Since \frac{3x+1}{\left(x-1\right)\left(x+1\right)} and \frac{2\left(-1\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)} have the same denominator, add them by adding their numerators.
\frac{3x+1-2x-2}{\left(x-1\right)\left(x+1\right)}-\frac{3}{1+x}
Do the multiplications in 3x+1+2\left(-1\right)\left(x+1\right).
\frac{x-1}{\left(x-1\right)\left(x+1\right)}-\frac{3}{1+x}
Combine like terms in 3x+1-2x-2.
\frac{1}{x+1}-\frac{3}{1+x}
Cancel out x-1 in both numerator and denominator.
\frac{-2}{x+1}
Since \frac{1}{x+1} and \frac{3}{1+x} have the same denominator, subtract them by subtracting their numerators. Subtract 3 from 1 to get -2.
\frac{3x+1}{\left(x-1\right)\left(x+1\right)}+\frac{2}{1-x}-\frac{3}{1+x}
Factor x^{2}-1.
\frac{3x+1}{\left(x-1\right)\left(x+1\right)}+\frac{2\left(-1\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}-\frac{3}{1+x}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of \left(x-1\right)\left(x+1\right) and 1-x is \left(x-1\right)\left(x+1\right). Multiply \frac{2}{1-x} times \frac{-\left(x+1\right)}{-\left(x+1\right)}.
\frac{3x+1+2\left(-1\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}-\frac{3}{1+x}
Since \frac{3x+1}{\left(x-1\right)\left(x+1\right)} and \frac{2\left(-1\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)} have the same denominator, add them by adding their numerators.
\frac{3x+1-2x-2}{\left(x-1\right)\left(x+1\right)}-\frac{3}{1+x}
Do the multiplications in 3x+1+2\left(-1\right)\left(x+1\right).
\frac{x-1}{\left(x-1\right)\left(x+1\right)}-\frac{3}{1+x}
Combine like terms in 3x+1-2x-2.
\frac{1}{x+1}-\frac{3}{1+x}
Cancel out x-1 in both numerator and denominator.
\frac{-2}{x+1}
Since \frac{1}{x+1} and \frac{3}{1+x} have the same denominator, subtract them by subtracting their numerators. Subtract 3 from 1 to get -2.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}