Skip to main content
Solve for x
Tick mark Image
Graph

Similar Problems from Web Search

Share

\left(10x-3\right)\left(3x+1\right)=\left(5x+7\right)\left(6x+11\right)
Variable x cannot be equal to any of the values -\frac{7}{5},\frac{3}{10} since division by zero is not defined. Multiply both sides of the equation by \left(10x-3\right)\left(5x+7\right), the least common multiple of 5x+7,10x-3.
30x^{2}+x-3=\left(5x+7\right)\left(6x+11\right)
Use the distributive property to multiply 10x-3 by 3x+1 and combine like terms.
30x^{2}+x-3=30x^{2}+97x+77
Use the distributive property to multiply 5x+7 by 6x+11 and combine like terms.
30x^{2}+x-3-30x^{2}=97x+77
Subtract 30x^{2} from both sides.
x-3=97x+77
Combine 30x^{2} and -30x^{2} to get 0.
x-3-97x=77
Subtract 97x from both sides.
-96x-3=77
Combine x and -97x to get -96x.
-96x=77+3
Add 3 to both sides.
-96x=80
Add 77 and 3 to get 80.
x=\frac{80}{-96}
Divide both sides by -96.
x=-\frac{5}{6}
Reduce the fraction \frac{80}{-96} to lowest terms by extracting and canceling out 16.