Solve 3x+1/4>1+4-x/12

$$\frac { 3 x + 1 } { 4 } > 1 + \frac { 4 - x } { 12 }$$

Solve for x

$$x>\frac{13}{10}$$

Solution Steps

Multiply both sides of the equation by 12, the least common multiple of 4,12. Since 12 is positive, the inequality direction remains the same.

$$3\left(3x+1\right)>12+4-x$$

Use the distributive property to multiply 3 by 3x+1.

$$9x+3>12+4-x$$

Add 12 and 4 to get 16.

$$9x+3>16-x$$

Add x to both sides.

$$9x+3+x>16$$

Combine 9x and x to get 10x.

$$10x+3>16$$

Subtract 3 from both sides.

$$10x>16-3$$

Subtract 3 from 16 to get 13.

$$10x>13$$

Divide both sides by 10. Since 10 is positive, the inequality direction remains the same.

$$x>\frac{13}{10}$$