Solve 3x+1/2-3=x

$$\frac { 3 x + 1 } { 2 } - 3 = x$$

Solve for x

$$x=5$$

Steps for Solving Linear Equation

Divide each term of 3x+1 by 2 to get \frac{3}{2}x+\frac{1}{2}.

$$\frac{3}{2}x+\frac{1}{2}-3=x$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{3}{2}x+\frac{1}{2}-\frac{6}{2}=x$$

Since \frac{1}{2} and \frac{6}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{2}x+\frac{1-6}{2}=x$$

Subtract 6 from 1 to get -5.

$$\frac{3}{2}x-\frac{5}{2}=x$$

Subtract x from both sides.

$$\frac{3}{2}x-\frac{5}{2}-x=0$$

Combine \frac{3}{2}x and -x to get \frac{1}{2}x.

$$\frac{1}{2}x-\frac{5}{2}=0$$

Add \frac{5}{2} to both sides. Anything plus zero gives itself.

$$\frac{1}{2}x=\frac{5}{2}$$

Multiply both sides by 2, the reciprocal of \frac{1}{2}.

$$x=\frac{5}{2}\times 2$$

Cancel out 2 and 2.

$$x=5$$