Solve 3q+18/16q^7*32q^7/9q+54

$$\frac { 3 q + 18 } { 16 q ^ { 7 } } \cdot \frac { 32 q ^ { 7 } } { 9 q + 54 }$$

Evaluate

$$\frac{2}{3}\approx 0.666666667$$

Short Solution Steps

Multiply \frac{3q+18}{16q^{7}} times \frac{32q^{7}}{9q+54} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(3q+18\right)\times 32q^{7}}{16q^{7}\left(9q+54\right)}$$

Cancel out 16q^{7} in both numerator and denominator.

$$\frac{2\left(3q+18\right)}{9q+54}$$

Factor the expressions that are not already factored.

$$\frac{2\times 3\left(q+6\right)}{9\left(q+6\right)}$$

Cancel out 3\left(q+6\right) in both numerator and denominator.

$$\frac{2}{3}$$

Factor

$$\frac{2}{3} = 0.6666666666666666$$