Solve 3m/p=2q/m

$$\frac { 3 m } { p } = \frac { 2 q } { m }$$

Solve for p

$$p=\frac{3m^{2}}{2q}$$

$$m\neq 0\text{ and }q\neq 0$$

Steps for Solving Linear Equation

Variable p cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by mp, the least common multiple of p,m.

$$m\times 3m=p\times 2q$$

Multiply m and m to get m^{2}.

$$m^{2}\times 3=p\times 2q$$

Swap sides so that all variable terms are on the left hand side.

$$p\times 2q=m^{2}\times 3$$

The equation is in standard form.

$$2qp=3m^{2}$$

Divide both sides by 2q.

$$\frac{2qp}{2q}=\frac{3m^{2}}{2q}$$

Dividing by 2q undoes the multiplication by 2q.

$$p=\frac{3m^{2}}{2q}$$

Variable p cannot be equal to 0.

$$p=\frac{3m^{2}}{2q}\text{, }p\neq 0$$

Solve for m

$$m=\frac{\sqrt{6pq}}{3}$$

$$m=-\frac{\sqrt{6pq}}{3}\text{, }\left(q<0\text{ and }p<0\right)\text{ or }\left(p>0\text{ and }q>0\right)$$