Solve 3m/m-n*2mn/n-2m

$$\frac { 3 m } { m - n } \times \frac { 2 m n } { n - 2 m }$$

Evaluate

$$\frac{6nm^{2}}{\left(m-n\right)\left(n-2m\right)}$$

Short Solution Steps

Multiply \frac{3m}{m-n} times \frac{2mn}{n-2m} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3m\times 2mn}{\left(m-n\right)\left(n-2m\right)}$$

Multiply m and m to get m^{2}.

$$\frac{3m^{2}\times 2n}{\left(m-n\right)\left(n-2m\right)}$$

Multiply 3 and 2 to get 6.

$$\frac{6m^{2}n}{\left(m-n\right)\left(n-2m\right)}$$

Apply the distributive property by multiplying each term of m-n by each term of n-2m.

$$\frac{6m^{2}n}{mn-2m^{2}-n^{2}+2nm}$$

Combine mn and 2nm to get 3mn.

$$\frac{6m^{2}n}{3mn-2m^{2}-n^{2}}$$

Factor

$$\frac{6nm^{2}}{\left(m-n\right)\left(n-2m\right)}$$