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Solve for f
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3\times 3f=2f
Multiply both sides of the equation by 6, the least common multiple of 2,3.
9f=2f
Multiply 3 and 3 to get 9.
9f-2f=0
Subtract 2f from both sides.
7f=0
Combine 9f and -2f to get 7f.
f=0
Product of two numbers is equal to 0 if at least one of them is 0. Since 7 is not equal to 0, f must be equal to 0.