\frac { 3 d ^ { 2 } y } { d x ^ { 2 } } + \frac { 10 d y } { d x } - 20 y = 6 x ^ { 2 }
Solve for d
d=\frac{2x^{4}}{y}+\frac{20x^{2}}{3}-\frac{10x}{3}
\left(x=\frac{1}{2}\text{ or }y\neq -\frac{3x^{3}}{5\left(2x-1\right)}\right)\text{ and }x\neq 0\text{ and }y\neq 0
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