Solve 3b^5-48b/3b^4-12b^3+12b^2

$$\frac { 3 b ^ { 5 } - 48 b } { 3 b ^ { 4 } - 12 b ^ { 3 } + 12 b ^ { 2 } }$$

Evaluate

$$\frac{\left(b+2\right)\left(b^{2}+4\right)}{b\left(b-2\right)}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{3b\left(b-2\right)\left(b+2\right)\left(b^{2}+4\right)}{3b^{2}\left(b-2\right)^{2}}$$

Cancel out 3b\left(b-2\right) in both numerator and denominator.

$$\frac{\left(b+2\right)\left(b^{2}+4\right)}{b\left(b-2\right)}$$

Expand the expression.

$$\frac{b^{3}+2b^{2}+4b+8}{b^{2}-2b}$$

Expand

$$\frac{b^{3}+2b^{2}+4b+8}{b^{2}-2b}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{3b\left(b-2\right)\left(b+2\right)\left(b^{2}+4\right)}{3b^{2}\left(b-2\right)^{2}}$$

Cancel out 3b\left(b-2\right) in both numerator and denominator.

$$\frac{\left(b+2\right)\left(b^{2}+4\right)}{b\left(b-2\right)}$$

Expand the expression.

$$\frac{b^{3}+2b^{2}+4b+8}{b^{2}-2b}$$