Solve 3b^2/x-3=360/3x

$$\frac { 3 b ^ { 2 } } { x } - 3 = \frac { 360 } { 3 x }$$

Solve for x (complex solution)

$$x=b^{2}-40$$

$$b\neq -2\sqrt{10}\text{ and }b\neq 2\sqrt{10}$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 3x, the least common multiple of x,3x.

$$3\times 3b^{2}+3x\left(-3\right)=360$$

Multiply 3 and 3 to get 9.

$$9b^{2}+3x\left(-3\right)=360$$

Multiply 3 and -3 to get -9.

$$9b^{2}-9x=360$$

Subtract 9b^{2} from both sides.

$$-9x=360-9b^{2}$$

Divide both sides by -9.

$$\frac{-9x}{-9}=\frac{360-9b^{2}}{-9}$$

Dividing by -9 undoes the multiplication by -9.

$$x=\frac{360-9b^{2}}{-9}$$

Divide 360-9b^{2} by -9.

$$x=b^{2}-40$$

Variable x cannot be equal to 0.

$$x=b^{2}-40\text{, }x\neq 0$$

Solve for x

$$x=b^{2}-40$$

$$|b|\neq 2\sqrt{10}$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 3x, the least common multiple of x,3x.

$$3\times 3b^{2}+3x\left(-3\right)=360$$

Multiply 3 and 3 to get 9.

$$9b^{2}+3x\left(-3\right)=360$$

Multiply 3 and -3 to get -9.

$$9b^{2}-9x=360$$

Subtract 9b^{2} from both sides.

$$-9x=360-9b^{2}$$

Divide both sides by -9.

$$\frac{-9x}{-9}=\frac{360-9b^{2}}{-9}$$

Dividing by -9 undoes the multiplication by -9.

$$x=\frac{360-9b^{2}}{-9}$$

Divide 360-9b^{2} by -9.

$$x=b^{2}-40$$

Variable x cannot be equal to 0.

$$x=b^{2}-40\text{, }x\neq 0$$

Solve for b (complex solution)

$$b=-\sqrt{x+40}$$

$$b=\sqrt{x+40}\text{, }x\neq 0$$

Solve for b

$$b=\sqrt{x+40}$$

$$b=-\sqrt{x+40}\text{, }x\geq -40\text{ and }x\neq 0$$