Solve 3a/5=/20bc

$$\frac { 3 a } { 5 } = \frac { } { 20 b c }$$

Solve for a

$$a=\frac{1}{12bc}$$

$$c\neq 0\text{ and }b\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 20bc, the least common multiple of 5,20bc.

$$4bc\times 3a=1$$

Multiply 4 and 3 to get 12.

$$12bca=1$$

Divide both sides by 12bc.

$$\frac{12bca}{12bc}=\frac{1}{12bc}$$

Dividing by 12bc undoes the multiplication by 12bc.

$$a=\frac{1}{12bc}$$

Solve for b

$$b=\frac{1}{12ac}$$

$$a\neq 0\text{ and }c\neq 0$$

Steps for Solving Linear Equation

Variable b cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 20bc, the least common multiple of 5,20bc.

$$4bc\times 3a=1$$

Multiply 4 and 3 to get 12.

$$12bca=1$$

The equation is in standard form.

$$12acb=1$$

Divide both sides by 12ca.

$$\frac{12acb}{12ac}=\frac{1}{12ac}$$

Dividing by 12ca undoes the multiplication by 12ca.

$$b=\frac{1}{12ac}$$

Variable b cannot be equal to 0.

$$b=\frac{1}{12ac}\text{, }b\neq 0$$