Solve for a
a=-\frac{4b}{9}+\frac{8}{3}
Solve for b
b=-\frac{9a}{4}+6
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3\times 3a+2\times 2b=24
Multiply both sides of the equation by 6, the least common multiple of 2,3.
9a+2\times 2b=24
Multiply 3 and 3 to get 9.
9a+4b=24
Multiply 2 and 2 to get 4.
9a=24-4b
Subtract 4b from both sides.
\frac{9a}{9}=\frac{24-4b}{9}
Divide both sides by 9.
a=\frac{24-4b}{9}
Dividing by 9 undoes the multiplication by 9.
a=-\frac{4b}{9}+\frac{8}{3}
Divide 24-4b by 9.
3\times 3a+2\times 2b=24
Multiply both sides of the equation by 6, the least common multiple of 2,3.
9a+2\times 2b=24
Multiply 3 and 3 to get 9.
9a+4b=24
Multiply 2 and 2 to get 4.
4b=24-9a
Subtract 9a from both sides.
\frac{4b}{4}=\frac{24-9a}{4}
Divide both sides by 4.
b=\frac{24-9a}{4}
Dividing by 4 undoes the multiplication by 4.
b=-\frac{9a}{4}+6
Divide 24-9a by 4.
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