Solve frac{3a^{5}b*(-12a^4b^2)}{4a^3b^2}=

$$\frac { 3 a ^ { 5 } b \cdot ( - 12 a ^ { 4 } b ^ { 2 } ) } { 4 a ^ { 3 } b ^ { 2 } } =$$

Evaluate

$$-9ba^{6}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 5 and 4 to get 9.

$$\frac{3a^{9}b\left(-12\right)b^{2}}{4a^{3}b^{2}}$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$\frac{3a^{9}b^{3}\left(-12\right)}{4a^{3}b^{2}}$$

Cancel out 4b^{2}a^{3} in both numerator and denominator.

$$-3\times 3ba^{6}$$

Multiply -3 and 3 to get -9.

$$-9ba^{6}$$

Differentiate w.r.t. b

$$-9a^{6}$$