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Evaluate (complex solution)
true
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Solve for y
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Solve for a
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\frac{3a^{2}\times 15y^{2}}{5y\times 9a^{3}}=\frac{3a^{2}\times 15y^{2}}{5y\times 9a^{3}}\text{ and }\frac{3a^{2}\times 15y^{2}}{5y\times 9a^{3}}=\frac{y}{a}
Divide \frac{3a^{2}}{5y} by \frac{9a^{3}}{15y^{2}} by multiplying \frac{3a^{2}}{5y} by the reciprocal of \frac{9a^{3}}{15y^{2}}.
\frac{y}{a}=\frac{3a^{2}\times 15y^{2}}{5y\times 9a^{3}}\text{ and }\frac{3a^{2}\times 15y^{2}}{5y\times 9a^{3}}=\frac{y}{a}
Cancel out 3\times 3\times 5ya^{2} in both numerator and denominator.
\frac{y}{a}=\frac{y}{a}\text{ and }\frac{3a^{2}\times 15y^{2}}{5y\times 9a^{3}}=\frac{y}{a}
Cancel out 3\times 3\times 5ya^{2} in both numerator and denominator.
\frac{y}{a}=\frac{y}{a}\text{ and }\frac{y}{a}=\frac{y}{a}
Cancel out 3\times 3\times 5ya^{2} in both numerator and denominator.
\frac{y}{a}-\frac{y}{a}=0\text{ and }\frac{y}{a}=\frac{y}{a}
Subtract \frac{y}{a} from both sides.
0=0\text{ and }\frac{y}{a}=\frac{y}{a}
Subtract \frac{y}{a} from \frac{y}{a} to get 0.
\text{true}\text{ and }\frac{y}{a}=\frac{y}{a}
Compare 0 and 0.
\text{true}\text{ and }\frac{y}{a}-\frac{y}{a}=0
Subtract \frac{y}{a} from both sides.
\text{true}\text{ and }0=0
Subtract \frac{y}{a} from \frac{y}{a} to get 0.
\text{true}\text{ and }\text{true}
Compare 0 and 0.
\text{true}
The conjunction of \text{true} and \text{true} is \text{true}.