Solve 3a+b/2=x

$$\frac { 3 a + b } { 2 } = x$$

Solve for a

$$a=\frac{2x-b}{3}$$

Steps for Solving Linear Equation

Divide each term of 3a+b by 2 to get \frac{3}{2}a+\frac{1}{2}b.

$$\frac{3}{2}a+\frac{1}{2}b=x$$

Subtract \frac{1}{2}b from both sides.

$$\frac{3}{2}a=x-\frac{1}{2}b$$

The equation is in standard form.

$$\frac{3}{2}a=-\frac{b}{2}+x$$

Divide both sides of the equation by \frac{3}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{2}a}{\frac{3}{2}}=\frac{-\frac{b}{2}+x}{\frac{3}{2}}$$

Dividing by \frac{3}{2} undoes the multiplication by \frac{3}{2}.

$$a=\frac{-\frac{b}{2}+x}{\frac{3}{2}}$$

Divide x-\frac{b}{2} by \frac{3}{2} by multiplying x-\frac{b}{2} by the reciprocal of \frac{3}{2}.

$$a=\frac{2x-b}{3}$$

Solve for b

$$b=2x-3a$$

Steps for Solving Linear Equation

Divide each term of 3a+b by 2 to get \frac{3}{2}a+\frac{1}{2}b.

$$\frac{3}{2}a+\frac{1}{2}b=x$$

Subtract \frac{3}{2}a from both sides.

$$\frac{1}{2}b=x-\frac{3}{2}a$$

The equation is in standard form.

$$\frac{1}{2}b=-\frac{3a}{2}+x$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}b}{\frac{1}{2}}=\frac{-\frac{3a}{2}+x}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$b=\frac{-\frac{3a}{2}+x}{\frac{1}{2}}$$

Divide x-\frac{3a}{2} by \frac{1}{2} by multiplying x-\frac{3a}{2} by the reciprocal of \frac{1}{2}.

$$b=2x-3a$$