Solve for B
B=60-a
Solve for a
a=60-B
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3a+3B=180
Multiply both sides of the equation by 3.
3B=180-3a
Subtract 3a from both sides.
\frac{3B}{3}=\frac{180-3a}{3}
Divide both sides by 3.
B=\frac{180-3a}{3}
Dividing by 3 undoes the multiplication by 3.
B=60-a
Divide 180-3a by 3.
3a+3B=180
Multiply both sides of the equation by 3.
3a=180-3B
Subtract 3B from both sides.
\frac{3a}{3}=\frac{180-3B}{3}
Divide both sides by 3.
a=\frac{180-3B}{3}
Dividing by 3 undoes the multiplication by 3.
a=60-B
Divide 180-3B by 3.
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