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x+1>0 x+1<0
Denominator x+1 cannot be zero since division by zero is not defined. There are two cases.
x>-1
Consider the case when x+1 is positive. Move 1 to the right hand side.
3-x<-2\left(x+1\right)
The initial inequality does not change the direction when multiplied by x+1 for x+1>0.
3-x<-2x-2
Multiply out the right hand side.
-x+2x<-3-2
Move the terms containing x to the left hand side and all other terms to the right hand side.
x<-5
Combine like terms.
x\in \emptyset
Consider condition x>-1 specified above.
x<-1
Now consider the case when x+1 is negative. Move 1 to the right hand side.
3-x>-2\left(x+1\right)
The initial inequality changes the direction when multiplied by x+1 for x+1<0.
3-x>-2x-2
Multiply out the right hand side.
-x+2x>-3-2
Move the terms containing x to the left hand side and all other terms to the right hand side.
x>-5
Combine like terms.
x\in \left(-5,-1\right)
Consider condition x<-1 specified above.
x\in \left(-5,-1\right)
The final solution is the union of the obtained solutions.