Evaluate
-1-\frac{1}{2}i=-1-0.5i
Real Part
-1
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\frac{\left(3-6i\right)i}{6i^{2}}
Multiply both numerator and denominator by imaginary unit i.
\frac{\left(3-6i\right)i}{-6}
By definition, i^{2} is -1. Calculate the denominator.
\frac{3i-6i^{2}}{-6}
Multiply 3-6i times i.
\frac{3i-6\left(-1\right)}{-6}
By definition, i^{2} is -1.
\frac{6+3i}{-6}
Do the multiplications in 3i-6\left(-1\right). Reorder the terms.
-1-\frac{1}{2}i
Divide 6+3i by -6 to get -1-\frac{1}{2}i.
Re(\frac{\left(3-6i\right)i}{6i^{2}})
Multiply both numerator and denominator of \frac{3-6i}{6i} by imaginary unit i.
Re(\frac{\left(3-6i\right)i}{-6})
By definition, i^{2} is -1. Calculate the denominator.
Re(\frac{3i-6i^{2}}{-6})
Multiply 3-6i times i.
Re(\frac{3i-6\left(-1\right)}{-6})
By definition, i^{2} is -1.
Re(\frac{6+3i}{-6})
Do the multiplications in 3i-6\left(-1\right). Reorder the terms.
Re(-1-\frac{1}{2}i)
Divide 6+3i by -6 to get -1-\frac{1}{2}i.
-1
The real part of -1-\frac{1}{2}i is -1.
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Limits
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