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\frac{\left(3-3i\right)i}{7i^{2}}
Multiply both numerator and denominator by imaginary unit i.
\frac{\left(3-3i\right)i}{-7}
By definition, i^{2} is -1. Calculate the denominator.
\frac{3i-3i^{2}}{-7}
Multiply 3-3i times i.
\frac{3i-3\left(-1\right)}{-7}
By definition, i^{2} is -1.
\frac{3+3i}{-7}
Do the multiplications in 3i-3\left(-1\right). Reorder the terms.
-\frac{3}{7}-\frac{3}{7}i
Divide 3+3i by -7 to get -\frac{3}{7}-\frac{3}{7}i.
Re(\frac{\left(3-3i\right)i}{7i^{2}})
Multiply both numerator and denominator of \frac{3-3i}{7i} by imaginary unit i.
Re(\frac{\left(3-3i\right)i}{-7})
By definition, i^{2} is -1. Calculate the denominator.
Re(\frac{3i-3i^{2}}{-7})
Multiply 3-3i times i.
Re(\frac{3i-3\left(-1\right)}{-7})
By definition, i^{2} is -1.
Re(\frac{3+3i}{-7})
Do the multiplications in 3i-3\left(-1\right). Reorder the terms.
Re(-\frac{3}{7}-\frac{3}{7}i)
Divide 3+3i by -7 to get -\frac{3}{7}-\frac{3}{7}i.
-\frac{3}{7}
The real part of -\frac{3}{7}-\frac{3}{7}i is -\frac{3}{7}.