Solve 3(4x-2)/6=41x/2-3(x+1)/5

$$\frac { 3 ( 4 x - 2 ) } { 6 } = \frac { 41 x } { 2 } - \frac { 3 ( x + 1 ) } { 5 }$$

Solve for x

$$x=-\frac{4}{179}\approx -0.022346369$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 30, the least common multiple of 6,2,5.

$$5\times 3\left(4x-2\right)=15\times 41x-6\times 3\left(x+1\right)$$

Multiply 5 and 3 to get 15.

$$15\left(4x-2\right)=15\times 41x-6\times 3\left(x+1\right)$$

Use the distributive property to multiply 15 by 4x-2.

$$60x-30=15\times 41x-6\times 3\left(x+1\right)$$

Multiply 15 and 41 to get 615. Multiply -6 and 3 to get -18.

$$60x-30=615x-18\left(x+1\right)$$

Use the distributive property to multiply -18 by x+1.

$$60x-30=615x-18x-18$$

Combine 615x and -18x to get 597x.

$$60x-30=597x-18$$

Subtract 597x from both sides.

$$60x-30-597x=-18$$

Combine 60x and -597x to get -537x.

$$-537x-30=-18$$

Add 30 to both sides.

$$-537x=-18+30$$

Add -18 and 30 to get 12.

$$-537x=12$$

Divide both sides by -537.

$$x=\frac{12}{-537}$$

Reduce the fraction \frac{12}{-537} to lowest terms by extracting and canceling out 3.

$$x=-\frac{4}{179}$$