Solve 3(1)+4(2)-7/3(-2)+4(1)-7=-4/-9=4/9

$$\frac { 3 ( 1 ) + 4 ( 2 ) - 7 } { 3 ( - 2 ) + 4 ( 1 ) - 7 } = - \frac { 4 } { - 9 } = \frac { 4 } { 9 }$$

Verify

Solution Steps

Multiply 3 and 1 to get 3. Multiply 4 and 2 to get 8.

$$\frac{3+8-7}{3\left(-2\right)+4\times 1-7}=-\frac{4}{-9}\text{ and }-\frac{4}{-9}=\frac{4}{9}$$

Add 3 and 8 to get 11.

$$\frac{11-7}{3\left(-2\right)+4\times 1-7}=-\frac{4}{-9}\text{ and }-\frac{4}{-9}=\frac{4}{9}$$

Subtract 7 from 11 to get 4.

$$\frac{4}{3\left(-2\right)+4\times 1-7}=-\frac{4}{-9}\text{ and }-\frac{4}{-9}=\frac{4}{9}$$

Multiply 3 and -2 to get -6. Multiply 4 and 1 to get 4.

$$\frac{4}{-6+4-7}=-\frac{4}{-9}\text{ and }-\frac{4}{-9}=\frac{4}{9}$$

Add -6 and 4 to get -2.

$$\frac{4}{-2-7}=-\frac{4}{-9}\text{ and }-\frac{4}{-9}=\frac{4}{9}$$

Subtract 7 from -2 to get -9.

$$\frac{4}{-9}=-\frac{4}{-9}\text{ and }-\frac{4}{-9}=\frac{4}{9}$$

Fraction \frac{4}{-9} can be rewritten as -\frac{4}{9} by extracting the negative sign.

$$-\frac{4}{9}=-\frac{4}{-9}\text{ and }-\frac{4}{-9}=\frac{4}{9}$$

Fraction \frac{4}{-9} can be rewritten as -\frac{4}{9} by extracting the negative sign.

$$-\frac{4}{9}=-\left(-\frac{4}{9}\right)\text{ and }-\frac{4}{-9}=\frac{4}{9}$$

The opposite of -\frac{4}{9} is \frac{4}{9}.

$$-\frac{4}{9}=\frac{4}{9}\text{ and }-\frac{4}{-9}=\frac{4}{9}$$

Compare -\frac{4}{9} and \frac{4}{9}.

$$\text{false}\text{ and }-\frac{4}{-9}=\frac{4}{9}$$

Fraction \frac{4}{-9} can be rewritten as -\frac{4}{9} by extracting the negative sign.

$$\text{false}\text{ and }-\left(-\frac{4}{9}\right)=\frac{4}{9}$$

The opposite of -\frac{4}{9} is \frac{4}{9}.

$$\text{false}\text{ and }\frac{4}{9}=\frac{4}{9}$$

Compare \frac{4}{9} and \frac{4}{9}.

$$\text{false}\text{ and }\text{true}$$

The conjunction of \text{false} and \text{true} is \text{false}.

$$\text{false}$$