Solve for x
x=-30
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\left(2x+3\right)\times 3-\left(x-5\right)=\left(x-4\right)\times 4
Variable x cannot be equal to any of the values -\frac{3}{2},4 since division by zero is not defined. Multiply both sides of the equation by \left(x-4\right)\left(2x+3\right), the least common multiple of x-4,\left(x-4\right)\left(2x+3\right),2x+3.
6x+9-\left(x-5\right)=\left(x-4\right)\times 4
Use the distributive property to multiply 2x+3 by 3.
6x+9-x+5=\left(x-4\right)\times 4
To find the opposite of x-5, find the opposite of each term.
5x+9+5=\left(x-4\right)\times 4
Combine 6x and -x to get 5x.
5x+14=\left(x-4\right)\times 4
Add 9 and 5 to get 14.
5x+14=4x-16
Use the distributive property to multiply x-4 by 4.
5x+14-4x=-16
Subtract 4x from both sides.
x+14=-16
Combine 5x and -4x to get x.
x=-16-14
Subtract 14 from both sides.
x=-30
Subtract 14 from -16 to get -30.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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