Solve 3/x+4-y=8

$$\frac { 3 } { x } + 4 - y = 8$$

Solve for x

$$x=\frac{3}{y+4}$$

$$y\neq -4$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$3+x\times 4-yx=8x$$

Subtract 8x from both sides.

$$3+x\times 4-yx-8x=0$$

Combine x\times 4 and -8x to get -4x.

$$3-4x-yx=0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$-4x-yx=-3$$

Combine all terms containing x.

$$\left(-4-y\right)x=-3$$

The equation is in standard form.

$$\left(-y-4\right)x=-3$$

Divide both sides by -y-4.

$$\frac{\left(-y-4\right)x}{-y-4}=-\frac{3}{-y-4}$$

Dividing by -y-4 undoes the multiplication by -y-4.

$$x=-\frac{3}{-y-4}$$

Divide -3 by -y-4.

$$x=\frac{3}{y+4}$$

Variable x cannot be equal to 0.

$$x=\frac{3}{y+4}\text{, }x\neq 0$$

Solve for y

$$y=-4+\frac{3}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x.

$$3+x\times 4-yx=8x$$

Subtract 3 from both sides.

$$x\times 4-yx=8x-3$$

Subtract x\times 4 from both sides.

$$-yx=8x-3-x\times 4$$

Combine 8x and -x\times 4 to get 4x.

$$-yx=4x-3$$

The equation is in standard form.

$$\left(-x\right)y=4x-3$$

Divide both sides by -x.

$$\frac{\left(-x\right)y}{-x}=\frac{4x-3}{-x}$$

Dividing by -x undoes the multiplication by -x.

$$y=\frac{4x-3}{-x}$$

Divide 4x-3 by -x.

$$y=-4+\frac{3}{x}$$