Solve 3/x+2/3x^2=3/6x

$$\frac { 3 } { x } + \frac { 2 } { 3 x ^ { 2 } } = \frac { 3 } { 6 x }$$

Solve for x

$$x=-\frac{4}{15}\approx -0.266666667$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 6x^{2}, the least common multiple of x,3x^{2},6x.

$$6x\times 3+2\times 2=x\times 3$$

Multiply 6 and 3 to get 18.

$$18x+2\times 2=x\times 3$$

Multiply 2 and 2 to get 4.

$$18x+4=x\times 3$$

Subtract x\times 3 from both sides.

$$18x+4-x\times 3=0$$

Combine 18x and -x\times 3 to get 15x.

$$15x+4=0$$

Subtract 4 from both sides. Anything subtracted from zero gives its negation.

$$15x=-4$$

Divide both sides by 15.

$$x=\frac{-4}{15}$$

Fraction \frac{-4}{15} can be rewritten as -\frac{4}{15} by extracting the negative sign.

$$x=-\frac{4}{15}$$