Solve 3/r-3+9=r/r-3quad6

$$\frac { 3 } { r - 3 } + 9 = \frac { r } { r - 3 } \quad 6$$

Solve for r

$$r=8$$

Steps for Solving Linear Equation

Variable r cannot be equal to 3 since division by zero is not defined. Multiply both sides of the equation by r-3.

$$3+\left(r-3\right)\times 9=r\times 6$$

Use the distributive property to multiply r-3 by 9.

$$3+9r-27=r\times 6$$

Subtract 27 from 3 to get -24.

$$-24+9r=r\times 6$$

Subtract r\times 6 from both sides.

$$-24+9r-r\times 6=0$$

Combine 9r and -r\times 6 to get 3r.

$$-24+3r=0$$

Add 24 to both sides. Anything plus zero gives itself.

$$3r=24$$

Divide both sides by 3.

$$r=\frac{24}{3}$$

Divide 24 by 3 to get 8.

$$r=8$$