Solve for r
r=10
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\left(r-4\right)\times 3=\left(r-1\right)\times 2
Variable r cannot be equal to any of the values 1,4 since division by zero is not defined. Multiply both sides of the equation by \left(r-4\right)\left(r-1\right), the least common multiple of r-1,r-4.
3r-12=\left(r-1\right)\times 2
Use the distributive property to multiply r-4 by 3.
3r-12=2r-2
Use the distributive property to multiply r-1 by 2.
3r-12-2r=-2
Subtract 2r from both sides.
r-12=-2
Combine 3r and -2r to get r.
r=-2+12
Add 12 to both sides.
r=10
Add -2 and 12 to get 10.
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