Solve 3/n^2-4n-12-6/n^2-4n-12

$$\frac { 3 } { n ^ { 2 } - 4 n - 12 } - \frac { 6 } { n ^ { 2 } - 4 n - 12 }$$

Evaluate

$$-\frac{3}{\left(n-6\right)\left(n+2\right)}$$

Solution Steps

Since \frac{3}{n^{2}-4n-12} and \frac{6}{n^{2}-4n-12} have the same denominator, subtract them by subtracting their numerators. Subtract 6 from 3 to get -3.

$$\frac{-3}{n^{2}-4n-12}$$

Factor

$$-\frac{3}{\left(n-6\right)\left(n+2\right)}$$