Solve 3/b=7a+5

$$\frac { 3 } { b } = 7 a + 5$$

Solve for a

$$a=-\frac{5}{7}+\frac{3}{7b}$$

$$b\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by b.

$$3=7ab+b\times 5$$

Swap sides so that all variable terms are on the left hand side.

$$7ab+b\times 5=3$$

Subtract b\times 5 from both sides.

$$7ab=3-b\times 5$$

Multiply -1 and 5 to get -5.

$$7ab=3-5b$$

The equation is in standard form.

$$7ba=3-5b$$

Divide both sides by 7b.

$$\frac{7ba}{7b}=\frac{3-5b}{7b}$$

Dividing by 7b undoes the multiplication by 7b.

$$a=\frac{3-5b}{7b}$$

Divide 3-5b by 7b.

$$a=-\frac{5}{7}+\frac{3}{7b}$$

Solve for b

$$b=\frac{3}{7a+5}$$

$$a\neq -\frac{5}{7}$$

Steps for Solving Linear Equation

Variable b cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by b.

$$3=7ab+b\times 5$$

Swap sides so that all variable terms are on the left hand side.

$$7ab+b\times 5=3$$

Combine all terms containing b.

$$\left(7a+5\right)b=3$$

Divide both sides by 7a+5.

$$\frac{\left(7a+5\right)b}{7a+5}=\frac{3}{7a+5}$$

Dividing by 7a+5 undoes the multiplication by 7a+5.

$$b=\frac{3}{7a+5}$$

Variable b cannot be equal to 0.

$$b=\frac{3}{7a+5}\text{, }b\neq 0$$