Solve 3/9+1,2+10/9

$$\frac { 3 } { 9 } + 1,2 + \frac { 10 } { 9 }$$

Evaluate

$$\frac{119}{45}\approx 2,644444444$$

Solution Steps

Reduce the fraction \frac{3}{9} to lowest terms by extracting and canceling out 3.

$$\frac{1}{3}+1,2+\frac{10}{9}$$

Convert decimal number 1,2 to fraction \frac{12}{10}. Reduce the fraction \frac{12}{10} to lowest terms by extracting and canceling out 2.

$$\frac{1}{3}+\frac{6}{5}+\frac{10}{9}$$

Least common multiple of 3 and 5 is 15. Convert \frac{1}{3} and \frac{6}{5} to fractions with denominator 15.

$$\frac{5}{15}+\frac{18}{15}+\frac{10}{9}$$

Since \frac{5}{15} and \frac{18}{15} have the same denominator, add them by adding their numerators.

$$\frac{5+18}{15}+\frac{10}{9}$$

Add 5 and 18 to get 23.

$$\frac{23}{15}+\frac{10}{9}$$

Least common multiple of 15 and 9 is 45. Convert \frac{23}{15} and \frac{10}{9} to fractions with denominator 45.

$$\frac{69}{45}+\frac{50}{45}$$

Since \frac{69}{45} and \frac{50}{45} have the same denominator, add them by adding their numerators.

$$\frac{69+50}{45}$$

Add 69 and 50 to get 119.

$$\frac{119}{45}$$

Factor

$$\frac{7 \cdot 17}{5 \cdot 3 ^ {2}} = 2\frac{29}{45} = 2.6444444444444444$$