Solve 3/8x-1/4y=3

$$\frac { 3 } { 8 } x - \frac { 1 } { 4 } y = 3$$

Solve for x

$$x=\frac{2\left(y+12\right)}{3}$$

Steps for Solving Linear Equation

Add \frac{1}{4}y to both sides.

$$\frac{3}{8}x=3+\frac{1}{4}y$$

The equation is in standard form.

$$\frac{3}{8}x=\frac{y}{4}+3$$

Divide both sides of the equation by \frac{3}{8}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{8}x}{\frac{3}{8}}=\frac{\frac{y}{4}+3}{\frac{3}{8}}$$

Dividing by \frac{3}{8} undoes the multiplication by \frac{3}{8}.

$$x=\frac{\frac{y}{4}+3}{\frac{3}{8}}$$

Divide 3+\frac{y}{4} by \frac{3}{8} by multiplying 3+\frac{y}{4} by the reciprocal of \frac{3}{8}.

$$x=\frac{2y}{3}+8$$

Solve for y

$$y=\frac{3\left(x-8\right)}{2}$$

Steps for Solving Linear Equation

Subtract \frac{3}{8}x from both sides.

$$-\frac{1}{4}y=3-\frac{3}{8}x$$

The equation is in standard form.

$$-\frac{1}{4}y=-\frac{3x}{8}+3$$

Multiply both sides by -4.

$$\frac{-\frac{1}{4}y}{-\frac{1}{4}}=\frac{-\frac{3x}{8}+3}{-\frac{1}{4}}$$

Dividing by -\frac{1}{4} undoes the multiplication by -\frac{1}{4}.

$$y=\frac{-\frac{3x}{8}+3}{-\frac{1}{4}}$$

Divide 3-\frac{3x}{8} by -\frac{1}{4} by multiplying 3-\frac{3x}{8} by the reciprocal of -\frac{1}{4}.

$$y=\frac{3x}{2}-12$$