Solve 3/8x+3/4=-6

$$\frac { 3 } { 8 } x + \frac { 3 } { 4 } = - 6$$

Solve for x

$$x=-18$$

Steps for Solving Linear Equation

Subtract \frac{3}{4} from both sides.

$$\frac{3}{8}x=-6-\frac{3}{4}$$

Convert -6 to fraction -\frac{24}{4}.

$$\frac{3}{8}x=-\frac{24}{4}-\frac{3}{4}$$

Since -\frac{24}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{8}x=\frac{-24-3}{4}$$

Subtract 3 from -24 to get -27.

$$\frac{3}{8}x=-\frac{27}{4}$$

Multiply both sides by \frac{8}{3}, the reciprocal of \frac{3}{8}.

$$x=-\frac{27}{4}\times \frac{8}{3}$$

Multiply -\frac{27}{4} times \frac{8}{3} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{-27\times 8}{4\times 3}$$

Do the multiplications in the fraction \frac{-27\times 8}{4\times 3}.

$$x=\frac{-216}{12}$$

Divide -216 by 12 to get -18.

$$x=-18$$