Solve 3/8(h+1/2)+(-1/4)

$$\frac { 3 } { 8 } ( h + \frac { 1 } { 2 } ) + ( - \frac { 1 } { 4 } )$$

Evaluate

$$\frac{3h}{8}-\frac{1}{16}$$

Solution Steps

Use the distributive property to multiply \frac{3}{8} by h+\frac{1}{2}.

$$\frac{3}{8}h+\frac{3}{8}\times \frac{1}{2}-\frac{1}{4}$$

Multiply \frac{3}{8} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3}{8}h+\frac{3\times 1}{8\times 2}-\frac{1}{4}$$

Do the multiplications in the fraction \frac{3\times 1}{8\times 2}.

$$\frac{3}{8}h+\frac{3}{16}-\frac{1}{4}$$

Least common multiple of 16 and 4 is 16. Convert \frac{3}{16} and \frac{1}{4} to fractions with denominator 16.

$$\frac{3}{8}h+\frac{3}{16}-\frac{4}{16}$$

Since \frac{3}{16} and \frac{4}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{8}h+\frac{3-4}{16}$$

Subtract 4 from 3 to get -1.

$$\frac{3}{8}h-\frac{1}{16}$$

Expand

$$\frac{3h}{8}-\frac{1}{16}$$

Solution Steps

Use the distributive property to multiply \frac{3}{8} by h+\frac{1}{2}.

$$\frac{3}{8}h+\frac{3}{8}\times \frac{1}{2}-\frac{1}{4}$$

Multiply \frac{3}{8} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3}{8}h+\frac{3\times 1}{8\times 2}-\frac{1}{4}$$

Do the multiplications in the fraction \frac{3\times 1}{8\times 2}.

$$\frac{3}{8}h+\frac{3}{16}-\frac{1}{4}$$

Least common multiple of 16 and 4 is 16. Convert \frac{3}{16} and \frac{1}{4} to fractions with denominator 16.

$$\frac{3}{8}h+\frac{3}{16}-\frac{4}{16}$$

Since \frac{3}{16} and \frac{4}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{8}h+\frac{3-4}{16}$$

Subtract 4 from 3 to get -1.

$$\frac{3}{8}h-\frac{1}{16}$$