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\frac{3}{8}x=\frac{7}{12}-\frac{1}{3}
Subtract \frac{1}{3} from both sides.
\frac{3}{8}x=\frac{7}{12}-\frac{4}{12}
Least common multiple of 12 and 3 is 12. Convert \frac{7}{12} and \frac{1}{3} to fractions with denominator 12.
\frac{3}{8}x=\frac{7-4}{12}
Since \frac{7}{12} and \frac{4}{12} have the same denominator, subtract them by subtracting their numerators.
\frac{3}{8}x=\frac{3}{12}
Subtract 4 from 7 to get 3.
\frac{3}{8}x=\frac{1}{4}
Reduce the fraction \frac{3}{12} to lowest terms by extracting and canceling out 3.
x=\frac{1}{4}\times \frac{8}{3}
Multiply both sides by \frac{8}{3}, the reciprocal of \frac{3}{8}.
x=\frac{1\times 8}{4\times 3}
Multiply \frac{1}{4} times \frac{8}{3} by multiplying numerator times numerator and denominator times denominator.
x=\frac{8}{12}
Do the multiplications in the fraction \frac{1\times 8}{4\times 3}.
x=\frac{2}{3}
Reduce the fraction \frac{8}{12} to lowest terms by extracting and canceling out 4.