Solve 3/8+6/8-4/8=75/8

$$\frac { 3 } { 8 } + \frac { 6 } { 8 } - \frac { 4 } { 8 } = \frac { 75 } { 8 }$$

Verify

Solution Steps

Reduce the fraction \frac{6}{8} to lowest terms by extracting and canceling out 2.

$$\frac{3}{8}+\frac{3}{4}-\frac{4}{8}=\frac{75}{8}$$

Least common multiple of 8 and 4 is 8. Convert \frac{3}{8} and \frac{3}{4} to fractions with denominator 8.

$$\frac{3}{8}+\frac{6}{8}-\frac{4}{8}=\frac{75}{8}$$

Since \frac{3}{8} and \frac{6}{8} have the same denominator, add them by adding their numerators.

$$\frac{3+6}{8}-\frac{4}{8}=\frac{75}{8}$$

Add 3 and 6 to get 9.

$$\frac{9}{8}-\frac{4}{8}=\frac{75}{8}$$

Since \frac{9}{8} and \frac{4}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-4}{8}=\frac{75}{8}$$

Subtract 4 from 9 to get 5.

$$\frac{5}{8}=\frac{75}{8}$$

Compare \frac{5}{8} and \frac{75}{8}.

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