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\frac{3}{7}x=\frac{3}{5}+\frac{3}{8}
Add \frac{3}{8} to both sides.
\frac{3}{7}x=\frac{24}{40}+\frac{15}{40}
Least common multiple of 5 and 8 is 40. Convert \frac{3}{5} and \frac{3}{8} to fractions with denominator 40.
\frac{3}{7}x=\frac{24+15}{40}
Since \frac{24}{40} and \frac{15}{40} have the same denominator, add them by adding their numerators.
\frac{3}{7}x=\frac{39}{40}
Add 24 and 15 to get 39.
x=\frac{39}{40}\times \frac{7}{3}
Multiply both sides by \frac{7}{3}, the reciprocal of \frac{3}{7}.
x=\frac{39\times 7}{40\times 3}
Multiply \frac{39}{40} times \frac{7}{3} by multiplying numerator times numerator and denominator times denominator.
x=\frac{273}{120}
Do the multiplications in the fraction \frac{39\times 7}{40\times 3}.
x=\frac{91}{40}
Reduce the fraction \frac{273}{120} to lowest terms by extracting and canceling out 3.