Solve 3/7-(1/5*7/2)*3/5-frac{7}{3}

$$\frac { 3 } { 7 } - ( \frac { 1 } { 5 } \times \frac { 7 } { 2 } ) \times \frac { 3 } { 5 } - \frac { 7 } { 3 }$$

Evaluate

$$-\frac{2441}{1050}\approx -2.324761905$$

Solution Steps

Multiply \frac{1}{5} times \frac{7}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3}{7}-\frac{1\times 7}{5\times 2}\times \frac{3}{5}-\frac{7}{3}$$

Do the multiplications in the fraction \frac{1\times 7}{5\times 2}.

$$\frac{3}{7}-\frac{7}{10}\times \frac{3}{5}-\frac{7}{3}$$

Multiply \frac{7}{10} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3}{7}-\frac{7\times 3}{10\times 5}-\frac{7}{3}$$

Do the multiplications in the fraction \frac{7\times 3}{10\times 5}.

$$\frac{3}{7}-\frac{21}{50}-\frac{7}{3}$$

Least common multiple of 7 and 50 is 350. Convert \frac{3}{7} and \frac{21}{50} to fractions with denominator 350.

$$\frac{150}{350}-\frac{147}{350}-\frac{7}{3}$$

Since \frac{150}{350} and \frac{147}{350} have the same denominator, subtract them by subtracting their numerators.

$$\frac{150-147}{350}-\frac{7}{3}$$

Subtract 147 from 150 to get 3.

$$\frac{3}{350}-\frac{7}{3}$$

Least common multiple of 350 and 3 is 1050. Convert \frac{3}{350} and \frac{7}{3} to fractions with denominator 1050.

$$\frac{9}{1050}-\frac{2450}{1050}$$

Since \frac{9}{1050} and \frac{2450}{1050} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-2450}{1050}$$

Subtract 2450 from 9 to get -2441.

$$-\frac{2441}{1050}$$

Factor

$$-\frac{2441}{1050} = -2\frac{341}{1050} = -2.3247619047619046$$