Solve 3/7-4/5-8/9+3

$$\frac { 3 } { 7 } - \frac { 4 } { 5 } - \frac { 8 } { 9 } + 3$$

Evaluate

$$\frac{548}{315}\approx 1.73968254$$

Solution Steps

Least common multiple of 7 and 5 is 35. Convert \frac{3}{7} and \frac{4}{5} to fractions with denominator 35.

$$\frac{15}{35}-\frac{28}{35}-\frac{8}{9}+3$$

Since \frac{15}{35} and \frac{28}{35} have the same denominator, subtract them by subtracting their numerators.

$$\frac{15-28}{35}-\frac{8}{9}+3$$

Subtract 28 from 15 to get -13.

$$-\frac{13}{35}-\frac{8}{9}+3$$

Least common multiple of 35 and 9 is 315. Convert -\frac{13}{35} and \frac{8}{9} to fractions with denominator 315.

$$-\frac{117}{315}-\frac{280}{315}+3$$

Since -\frac{117}{315} and \frac{280}{315} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-117-280}{315}+3$$

Subtract 280 from -117 to get -397.

$$-\frac{397}{315}+3$$

Convert 3 to fraction \frac{945}{315}.

$$-\frac{397}{315}+\frac{945}{315}$$

Since -\frac{397}{315} and \frac{945}{315} have the same denominator, add them by adding their numerators.

$$\frac{-397+945}{315}$$

Add -397 and 945 to get 548.

$$\frac{548}{315}$$

Factor

$$\frac{2 ^ {2} \cdot 137}{3 ^ {2} \cdot 5 \cdot 7} = 1\frac{233}{315} = 1.7396825396825397$$