Solve 3/7(7/2+-7/8)]div[3/4+frac{7}{5}]

$$\frac { 3 } { 7 } ( \frac { 7 } { 2 } + - \frac { 7 } { 8 } ) ] \div [ \frac { 3 } { 4 } + \frac { 7 } { 5 } ]$$

Evaluate

$$\frac{9}{8}=1.125$$

Solution Steps

Least common multiple of 2 and 8 is 8. Convert \frac{7}{2} and \frac{7}{8} to fractions with denominator 8.

$$\frac{3}{7}\left(\frac{28}{8}-\frac{7}{8}\right)$$

Since \frac{28}{8} and \frac{7}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{7}\times \frac{28-7}{8}$$

Subtract 7 from 28 to get 21.

$$\frac{3}{7}\times \frac{21}{8}$$

Multiply \frac{3}{7} times \frac{21}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 21}{7\times 8}$$

Do the multiplications in the fraction \frac{3\times 21}{7\times 8}.

$$\frac{63}{56}$$

Reduce the fraction \frac{63}{56} to lowest terms by extracting and canceling out 7.

$$\frac{9}{8}$$

Factor

$$\frac{3 ^ {2}}{2 ^ {3}} = 1\frac{1}{8} = 1.125$$