Solve 3/7*35/2+15/13*26/-3

$$\frac { 3 } { 7 } \times \frac { 35 } { 2 } + \frac { 15 } { 13 } \times \frac { 26 } { - 3 }$$

Evaluate

$$-\frac{5}{2}=-2.5$$

Solution Steps

Multiply \frac{3}{7} times \frac{35}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 35}{7\times 2}+\frac{15}{13}\times \frac{26}{-3}$$

Do the multiplications in the fraction \frac{3\times 35}{7\times 2}.

$$\frac{105}{14}+\frac{15}{13}\times \frac{26}{-3}$$

Reduce the fraction \frac{105}{14} to lowest terms by extracting and canceling out 7.

$$\frac{15}{2}+\frac{15}{13}\times \frac{26}{-3}$$

Fraction \frac{26}{-3} can be rewritten as -\frac{26}{3} by extracting the negative sign.

$$\frac{15}{2}+\frac{15}{13}\left(-\frac{26}{3}\right)$$

Multiply \frac{15}{13} times -\frac{26}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{15}{2}+\frac{15\left(-26\right)}{13\times 3}$$

Do the multiplications in the fraction \frac{15\left(-26\right)}{13\times 3}.

$$\frac{15}{2}+\frac{-390}{39}$$

Divide -390 by 39 to get -10.

$$\frac{15}{2}-10$$

Convert 10 to fraction \frac{20}{2}.

$$\frac{15}{2}-\frac{20}{2}$$

Since \frac{15}{2} and \frac{20}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{15-20}{2}$$

Subtract 20 from 15 to get -5.

$$-\frac{5}{2}$$

Factor

$$-\frac{5}{2} = -2\frac{1}{2} = -2.5$$