Solve 3/7=21/98=21/105

$$\frac { 3 } { 7 } = \frac { 21 } { 98 } = \frac { 21 } { 105 }$$

Verify

Solution Steps

Reduce the fraction \frac{21}{98} to lowest terms by extracting and canceling out 7.

$$\frac{3}{7}=\frac{3}{14}\text{ and }\frac{21}{98}=\frac{21}{105}$$

Least common multiple of 7 and 14 is 14. Convert \frac{3}{7} and \frac{3}{14} to fractions with denominator 14.

$$\frac{6}{14}=\frac{3}{14}\text{ and }\frac{21}{98}=\frac{21}{105}$$

Compare \frac{6}{14} and \frac{3}{14}.

$$\text{false}\text{ and }\frac{21}{98}=\frac{21}{105}$$

Reduce the fraction \frac{21}{98} to lowest terms by extracting and canceling out 7.

$$\text{false}\text{ and }\frac{3}{14}=\frac{21}{105}$$

Reduce the fraction \frac{21}{105} to lowest terms by extracting and canceling out 21.

$$\text{false}\text{ and }\frac{3}{14}=\frac{1}{5}$$

Least common multiple of 14 and 5 is 70. Convert \frac{3}{14} and \frac{1}{5} to fractions with denominator 70.

$$\text{false}\text{ and }\frac{15}{70}=\frac{14}{70}$$

Compare \frac{15}{70} and \frac{14}{70}.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$