Solve 3/7+sqrt[3]{27/8}-(3/4)div(1/3)

$$\frac { 3 } { 7 } + \sqrt[ 3 ] { \frac { 27 } { 8 } } - ( \frac { 3 } { 4 } ) \div ( \frac { 1 } { 3 } )$$

Evaluate

$$-\frac{9}{28}\approx -0.321428571$$

Solution Steps

Calculate \sqrt[3]{\frac{27}{8}} and get \frac{3}{2}.

$$\frac{3}{7}+\frac{3}{2}-\frac{\frac{3}{4}}{\frac{1}{3}}$$

Add \frac{3}{7} and \frac{3}{2} to get \frac{27}{14}.

$$\frac{27}{14}-\frac{\frac{3}{4}}{\frac{1}{3}}$$

Divide \frac{3}{4} by \frac{1}{3} by multiplying \frac{3}{4} by the reciprocal of \frac{1}{3}.

$$\frac{27}{14}-\frac{3}{4}\times 3$$

Multiply \frac{3}{4} and 3 to get \frac{9}{4}.

$$\frac{27}{14}-\frac{9}{4}$$

Subtract \frac{9}{4} from \frac{27}{14} to get -\frac{9}{28}.

$$-\frac{9}{28}$$

Factor

$$-\frac{9}{28} = -0.32142857142857145$$