Solve 3/5x-5=-6quad[A]

$$\frac { 3 } { 5 } x - 5 = - 6 \quad [ A ]$$

Solve for A

$$A=-\frac{x}{10}+\frac{5}{6}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-6A=\frac{3}{5}x-5$$

The equation is in standard form.

$$-6A=\frac{3x}{5}-5$$

Divide both sides by -6.

$$\frac{-6A}{-6}=\frac{\frac{3x}{5}-5}{-6}$$

Dividing by -6 undoes the multiplication by -6.

$$A=\frac{\frac{3x}{5}-5}{-6}$$

Divide \frac{3x}{5}-5 by -6.

$$A=-\frac{x}{10}+\frac{5}{6}$$

Solve for x

$$x=\frac{25}{3}-10A$$

Steps for Solving Linear Equation

Add 5 to both sides.

$$\frac{3}{5}x=-6A+5$$

The equation is in standard form.

$$\frac{3}{5}x=5-6A$$

Divide both sides of the equation by \frac{3}{5}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{5}x}{\frac{3}{5}}=\frac{5-6A}{\frac{3}{5}}$$

Dividing by \frac{3}{5} undoes the multiplication by \frac{3}{5}.

$$x=\frac{5-6A}{\frac{3}{5}}$$

Divide -6A+5 by \frac{3}{5} by multiplying -6A+5 by the reciprocal of \frac{3}{5}.

$$x=\frac{25}{3}-10A$$