Solve 3/5x+8=1/10(x-40)

$$\frac { 3 } { 5 } x + 8 = \frac { 1 } { 10 } ( x - 40 )$$

Solve for x

$$x=-24$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{1}{10} by x-40.

$$\frac{3}{5}x+8=\frac{1}{10}x+\frac{1}{10}\left(-40\right)$$

Multiply \frac{1}{10} and -40 to get \frac{-40}{10}.

$$\frac{3}{5}x+8=\frac{1}{10}x+\frac{-40}{10}$$

Divide -40 by 10 to get -4.

$$\frac{3}{5}x+8=\frac{1}{10}x-4$$

Subtract \frac{1}{10}x from both sides.

$$\frac{3}{5}x+8-\frac{1}{10}x=-4$$

Combine \frac{3}{5}x and -\frac{1}{10}x to get \frac{1}{2}x.

$$\frac{1}{2}x+8=-4$$

Subtract 8 from both sides.

$$\frac{1}{2}x=-4-8$$

Subtract 8 from -4 to get -12.

$$\frac{1}{2}x=-12$$

Multiply both sides by 2, the reciprocal of \frac{1}{2}.

$$x=-12\times 2$$

Multiply -12 and 2 to get -24.

$$x=-24$$