Solve 3/5-7/1=3*7-5*7=

$$\frac { 3 } { 5 } - \frac { 7 } { 1 } = 3 \times 7 - 5 \times 7 =$$

Verify

Solution Steps

Anything divided by one gives itself.

$$\frac{3}{5}-7=3\times 7-5\times 7$$

Convert 7 to fraction \frac{35}{5}.

$$\frac{3}{5}-\frac{35}{5}=3\times 7-5\times 7$$

Since \frac{3}{5} and \frac{35}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-35}{5}=3\times 7-5\times 7$$

Subtract 35 from 3 to get -32.

$$-\frac{32}{5}=3\times 7-5\times 7$$

Multiply 3 and 7 to get 21.

$$-\frac{32}{5}=21-5\times 7$$

Multiply 5 and 7 to get 35.

$$-\frac{32}{5}=21-35$$

Subtract 35 from 21 to get -14.

$$-\frac{32}{5}=-14$$

Convert -14 to fraction -\frac{70}{5}.

$$-\frac{32}{5}=-\frac{70}{5}$$

Compare -\frac{32}{5} and -\frac{70}{5}.

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