Solve 3/5*(1/8+1/2)*40/3

$$\frac { 3 } { 5 } \cdot ( \frac { 1 } { 8 } + \frac { 1 } { 2 } ) \cdot \frac { 40 } { 3 }$$

Evaluate

$$5$$

Solution Steps

Least common multiple of 8 and 2 is 8. Convert \frac{1}{8} and \frac{1}{2} to fractions with denominator 8.

$$\frac{3}{5}\left(\frac{1}{8}+\frac{4}{8}\right)\times \frac{40}{3}$$

Since \frac{1}{8} and \frac{4}{8} have the same denominator, add them by adding their numerators.

$$\frac{3}{5}\times \frac{1+4}{8}\times \frac{40}{3}$$

Add 1 and 4 to get 5.

$$\frac{3}{5}\times \frac{5}{8}\times \frac{40}{3}$$

Multiply \frac{3}{5} times \frac{5}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 5}{5\times 8}\times \frac{40}{3}$$

Cancel out 5 in both numerator and denominator.

$$\frac{3}{8}\times \frac{40}{3}$$

Multiply \frac{3}{8} times \frac{40}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 40}{8\times 3}$$

Cancel out 3 in both numerator and denominator.

$$\frac{40}{8}$$

Divide 40 by 8 to get 5.

$$5$$

Factor

$$5$$