Solve 3/5+7/4+4/10=1

$$\frac { 3 } { 5 } + \frac { 7 } { 4 } + \frac { 4 } { 10 } = 1$$

Verify

Solution Steps

Least common multiple of 5 and 4 is 20. Convert \frac{3}{5} and \frac{7}{4} to fractions with denominator 20.

$$\frac{12}{20}+\frac{35}{20}+\frac{4}{10}=1$$

Since \frac{12}{20} and \frac{35}{20} have the same denominator, add them by adding their numerators.

$$\frac{12+35}{20}+\frac{4}{10}=1$$

Add 12 and 35 to get 47.

$$\frac{47}{20}+\frac{4}{10}=1$$

Reduce the fraction \frac{4}{10} to lowest terms by extracting and canceling out 2.

$$\frac{47}{20}+\frac{2}{5}=1$$

Least common multiple of 20 and 5 is 20. Convert \frac{47}{20} and \frac{2}{5} to fractions with denominator 20.

$$\frac{47}{20}+\frac{8}{20}=1$$

Since \frac{47}{20} and \frac{8}{20} have the same denominator, add them by adding their numerators.

$$\frac{47+8}{20}=1$$

Add 47 and 8 to get 55.

$$\frac{55}{20}=1$$

Reduce the fraction \frac{55}{20} to lowest terms by extracting and canceling out 5.

$$\frac{11}{4}=1$$

Convert 1 to fraction \frac{4}{4}.

$$\frac{11}{4}=\frac{4}{4}$$

Compare \frac{11}{4} and \frac{4}{4}.

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