Solve 3/5+2/3+1/4+7/2=

$$\frac { 3 } { 5 } + \frac { 2 } { 3 } + \frac { 1 } { 4 } + \frac { 7 } { 2 } =$$

Evaluate

$$\frac{301}{60}\approx 5.016666667$$

Solution Steps

Least common multiple of 5 and 3 is 15. Convert \frac{3}{5} and \frac{2}{3} to fractions with denominator 15.

$$\frac{9}{15}+\frac{10}{15}+\frac{1}{4}+\frac{7}{2}$$

Since \frac{9}{15} and \frac{10}{15} have the same denominator, add them by adding their numerators.

$$\frac{9+10}{15}+\frac{1}{4}+\frac{7}{2}$$

Add 9 and 10 to get 19.

$$\frac{19}{15}+\frac{1}{4}+\frac{7}{2}$$

Least common multiple of 15 and 4 is 60. Convert \frac{19}{15} and \frac{1}{4} to fractions with denominator 60.

$$\frac{76}{60}+\frac{15}{60}+\frac{7}{2}$$

Since \frac{76}{60} and \frac{15}{60} have the same denominator, add them by adding their numerators.

$$\frac{76+15}{60}+\frac{7}{2}$$

Add 76 and 15 to get 91.

$$\frac{91}{60}+\frac{7}{2}$$

Least common multiple of 60 and 2 is 60. Convert \frac{91}{60} and \frac{7}{2} to fractions with denominator 60.

$$\frac{91}{60}+\frac{210}{60}$$

Since \frac{91}{60} and \frac{210}{60} have the same denominator, add them by adding their numerators.

$$\frac{91+210}{60}$$

Add 91 and 210 to get 301.

$$\frac{301}{60}$$

Factor

$$\frac{7 \cdot 43}{2 ^ {2} \cdot 3 \cdot 5} = 5\frac{1}{60} = 5.016666666666667$$