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2\times 3+4\left(2x-3\right)\times \frac{1}{4}=4\times 5
Variable x cannot be equal to \frac{3}{2} since division by zero is not defined. Multiply both sides of the equation by 4\left(2x-3\right), the least common multiple of 4x-6,4,2x-3.
6+4\left(2x-3\right)\times \frac{1}{4}=4\times 5
Multiply 2 and 3 to get 6.
6+2x-3=4\times 5
Multiply 4 and \frac{1}{4} to get 1.
3+2x=4\times 5
Subtract 3 from 6 to get 3.
3+2x=20
Multiply 4 and 5 to get 20.
2x=20-3
Subtract 3 from both sides.
2x=17
Subtract 3 from 20 to get 17.
x=\frac{17}{2}
Divide both sides by 2.