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\frac{3\left(4+\sqrt{2}\right)}{\left(4-\sqrt{2}\right)\left(4+\sqrt{2}\right)}
Rationalize the denominator of \frac{3}{4-\sqrt{2}} by multiplying numerator and denominator by 4+\sqrt{2}.
\frac{3\left(4+\sqrt{2}\right)}{4^{2}-\left(\sqrt{2}\right)^{2}}
Consider \left(4-\sqrt{2}\right)\left(4+\sqrt{2}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{3\left(4+\sqrt{2}\right)}{16-2}
Square 4. Square \sqrt{2}.
\frac{3\left(4+\sqrt{2}\right)}{14}
Subtract 2 from 16 to get 14.
\frac{12+3\sqrt{2}}{14}
Use the distributive property to multiply 3 by 4+\sqrt{2}.